Homework Answers
Ss Ww * ss ww leads to
SsWw(90),ssww(90),Ssww(11),ssWw(11)
So individual hav parental genes and recombinant genes in a different ratio than normal.this shows that genes are linked and present on same chromosome.
When genes are linked than the inheritance pattern becomes shifted from the original 25% to a new no.
B)as we know that mendels second law holds true only when genes are not linked together.and that is why their are lower number of ssWw(11)-sable bodied normal wings and Ssww(11)-normal body with miniature wings.
Two allele combination on same chromosome will hav more than 25% with parental genes and less than 25% with recombinant genes.and dats y less number in recombinant genes.
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In Drosophilia, S normal. s-sable hody: W-normal., w miniature wing. In a cross between a heterozygous...
In Drosophilia, S = normal, s = sable body: W = normal, w = miniature wing....
In Drosophilia, S = normal, s = sable body: W = normal, w = miniature wing. In a cross between a heterozygous normal fly (heterozygous for both traits) and a sable-bodied, miniature-winged fly, the results were 90 normal flies, 90 with a sable body and miniature wings. 11 with a normal body and miniature wings, and 11 with a sable body and normal wings. Show your work What inheritance pattern explains these results? Why is the explanation for the small...
I included everything here , but i only need help with parts C-F You are working...
I included everything here , but i only need help with parts
C-F
You are working with a hypothetical fly and have found color and wing mutants. Preliminary work indicates that the mutant traits are recessive and the associated genes are not sex-linked, but beyond that you have no information. You first look at 2 genes, each with two alleles: "Borb" for body color and "Wor w" for wing surface. The red body phenotype is dominant to the yellow body...
could someone help me figure out how to do these pleaseeee A female fruit fly who...
could someone help me figure out how to do these
pleaseeee
A female fruit fly who is heterozygous with the phenotype gray body, red eyes & long wings is crossed with a male who is homozygous recessive (black body, purple eyes, vestigial wings). The observed offspring are shown below: # offspring, body color. eye color. wing length 411 gray red long 61 gray red vestigial 2 gray purple long 30 gray purple vestigial 28 black red long black red vestigial...
A gray-body fly with long wings is subjected to a test cross. The F1 progeny of...
A gray-body fly with long wings is subjected to a test cross. The F1 progeny of this test cross: Will only be of two phenotypes if the test cross fly is homozygous for both traits. Will only be of two phenotypes if the gray-bodied/long-winged fly is homozygous for both traits. Will be of four genotypes if the gray-bodies/long-winged fly is heterozygous for both traits. Will be of four genotypes if the test-cross fly is heterozygous for both traits. None of...
4. There are three genes on the X-chromosome in drosophila, yellow (y), white (w), and cut...
4. There are three genes on the X-chromosome in drosophila, yellow (y), white (w), and cut (ct). A yellow-bodied, white-eyed, and a homozygous normal winged female fly was crossed to a male with wild type body, wild type eyes, and cut wings. The Fi females were wild type for all three traits, while the Fi males had yellow bodies, white eyes, normal wings. The Fi females were crossed to yellow bodied, white eyed, cut wing males. The resulting F2 progeny...
A cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w), and cut (ch....
A cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w), and cut (ch. A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut . The F, females were wild type for all three traits. • The F, males expressed the yellow-body and white-eye traits. The cross was carried to an F2 progeny, and only male offspring were tallied. On the basis of the data...
im not sure how to calcualte the double crossover offspring A cross in Drosophila involved the...
im not sure how to calcualte the double crossover
offspring
A cross in Drosophila involved the recessive, X-linked genes yollow (y), white (w), and cut (ch). A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut • The F, females were wild type for all three traits. The F, males expressed the yellow-body and white-eye traits. The cross was carried to an F2 progeny, and only male...
Match the following terms with the appropriate description below: a. alleles b. autosomes c. dominant allele...
Match the following terms with the appropriate description
below:
a. alleles b. autosomes c. dominant allele d. genotype e.
heterozygous f. homozygote g. phenotype h. recessive allele i. sex
chromosomes
1. ________________ genetic make-up
2. ________________ how genetic make-up is expressed
3. ________________ chromosomes that dictate most body
characteristics
4. ________________ alternative forms of the same gene
5. ___________an individual bearing two alleles that are the same
for a particular trait 6. ________________ an allele that is
expressed, whether in...
can u tell me if these answers are correct please!??!!! Choose the best answer for the...
can
u tell me if these answers are correct please!??!!!
Choose the best answer for the following questions. Place your answer on the line. If your answer is not on the line.it does not count 1 Mender's discovery that characteristics are inherited due to the transmission of hereditary factors resulted from his (1) dissections to determine how fertilization occurs in pea plants (2analysis of the offspring produced from many pea plant crosses (3) careful microscopic examinations of genes and chromosomes...
In Drosophilia, S = normal, s = sable body: W = normal, w = miniature wing. In a cross between a heterozygous normal fly (heterozygous for both traits) and a sable-bodied, miniature-winged fly, the results were 90 normal flies, 90 with a sable body and miniature wings. 11 with a normal body and miniature wings, and 11 with a sable body and normal wings. Show your work What inheritance pattern explains these results? Why is the explanation for the small...
I included everything here , but i only need help with parts
C-F
You are working with a hypothetical fly and have found color and wing mutants. Preliminary work indicates that the mutant traits are recessive and the associated genes are not sex-linked, but beyond that you have no information. You first look at 2 genes, each with two alleles: "Borb" for body color and "Wor w" for wing surface. The red body phenotype is dominant to the yellow body...
could someone help me figure out how to do these
pleaseeee
A female fruit fly who is heterozygous with the phenotype gray body, red eyes & long wings is crossed with a male who is homozygous recessive (black body, purple eyes, vestigial wings). The observed offspring are shown below: # offspring, body color. eye color. wing length 411 gray red long 61 gray red vestigial 2 gray purple long 30 gray purple vestigial 28 black red long black red vestigial...
A gray-body fly with long wings is subjected to a test cross. The F1 progeny of this test cross: Will only be of two phenotypes if the test cross fly is homozygous for both traits. Will only be of two phenotypes if the gray-bodied/long-winged fly is homozygous for both traits. Will be of four genotypes if the gray-bodies/long-winged fly is heterozygous for both traits. Will be of four genotypes if the test-cross fly is heterozygous for both traits. None of...
4. There are three genes on the X-chromosome in drosophila, yellow (y), white (w), and cut (ct). A yellow-bodied, white-eyed, and a homozygous normal winged female fly was crossed to a male with wild type body, wild type eyes, and cut wings. The Fi females were wild type for all three traits, while the Fi males had yellow bodies, white eyes, normal wings. The Fi females were crossed to yellow bodied, white eyed, cut wing males. The resulting F2 progeny...
A cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w), and cut (ch. A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut . The F, females were wild type for all three traits. • The F, males expressed the yellow-body and white-eye traits. The cross was carried to an F2 progeny, and only male offspring were tallied. On the basis of the data...
im not sure how to calcualte the double crossover
offspring
A cross in Drosophila involved the recessive, X-linked genes yollow (y), white (w), and cut (ch). A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut • The F, females were wild type for all three traits. The F, males expressed the yellow-body and white-eye traits. The cross was carried to an F2 progeny, and only male...
Match the following terms with the appropriate description
below:
a. alleles b. autosomes c. dominant allele d. genotype e.
heterozygous f. homozygote g. phenotype h. recessive allele i. sex
chromosomes
1. ________________ genetic make-up
2. ________________ how genetic make-up is expressed
3. ________________ chromosomes that dictate most body
characteristics
4. ________________ alternative forms of the same gene
5. ___________an individual bearing two alleles that are the same
for a particular trait 6. ________________ an allele that is
expressed, whether in...
can
u tell me if these answers are correct please!??!!!
Choose the best answer for the following questions. Place your answer on the line. If your answer is not on the line.it does not count 1 Mender's discovery that characteristics are inherited due to the transmission of hereditary factors resulted from his (1) dissections to determine how fertilization occurs in pea plants (2analysis of the offspring produced from many pea plant crosses (3) careful microscopic examinations of genes and chromosomes...
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