A KMnO4 solution is standardized by a metallic iron primary standard. To do so, the metallic iron is dissolved in acid, reduced into Fe2+ and titrated by permanganate. If 33.00 mL of KMnO4 are required to titrate 0.5585 g of iron, what is the concentration of the permanganate solution?
The reaction is given as :
MnO4- + 8H+ + 5Fe2+ = Mn2+ + 4H2O + 5Fe3+
Number of moles of iron = 0.5585 / 55.85 = 0.01 mol
So number of moles of manganate required = 0.01 / 5 = 0.002 mol
Molarity = 0.002 / 0.033
= 0.06 M
So the concentartion of permanganate solution will be 0.06 M
A KMnO4 solution is standardized by a metallic iron primary standard. To do so, the metallic...
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You
have standardized your KMnO4- solution and the molarity is
0.03251M. You used 17.98ml to reach equivalence point with your
iron unknown. You started with 1.112g of unknown. What is the %Fe2+
in your unknown? (Fe2+ atomic weight=55.847 g/mol, KMnO4- formula
weight= 158.03g/mol)
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