Ans:
6)mean rate=6 per hour
a)
P(x=3)=exp(-6)*(6^3/3!)
=0.0892
b)
P(x<=3)=P(x=0)+P(x=1)+P(x=2)+P(x=3)
=exp(-6)*(6^0/0!+6^1/1!+6^2/2!+6^3/3!)
=0.1512
c)average number of customers in 2 hour=2*6=12
P(x=10)=exp(-12)*(12^10/10!)=0.1048
6. Customer arrivals at a check out counter have a Poison distribution with an average of...
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