Find the pH of the following :
0.50 M solution of a base with a Kb = 1.75 x 10-4

![Kb = [HAJ[OH-] 1.75X 10% = CA] x? 0.5-X, 2 = [OH-] = 9.267x103M pots - log Low-] pot er log (9.267x103)](http://img.homeworklib.com/questions/629f7120-c8da-11eb-907e-8db291fafb05.png?x-oss-process=image/resize,w_560)
![POH = 2.03 pH + Pot = 14 PH = 14-2.03 PH - 11,97]](http://img.homeworklib.com/questions/632be800-c8da-11eb-b0eb-f3eeafdac076.png?x-oss-process=image/resize,w_560)
Find the pH of the following : 0.50 M solution of a base with a Kb...
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