Homework Answers
The reaction is 2HBr+ Ba(OH)2 ------->BaBr2+2H2O
2 moles of HBr requires 1 mole of Ba(OH)2
moles= molarity* Volume in liters, 1000ml= 1L
moles of HBr= 0.1*27/1000=0.0027
hence moles of Ba(OH)2 required= moles of HBr/2= 0.0027/2=0.00135
volume of Ba(OH)2= 45.3 ml, converting this into liters, volume of Ba(OH)2= 45.3/1000=0.0453L
Hence concentration of Ba(OH)2= moles/Volume in liters= 0.00135/0.0453 moles/L=0.0298M
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