Question

Name: Assignment for 3/26/20 (20pts) Show all work for credit. 1) A flask containing 450.0 mL of 0.500 M HBr was spilled on the floor. How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following reaction? (10pts) 2 HBr (aq) + K2CO3 (s) - 2 KBr (aq) + CO2(g) + H2O (I) 2) Determine the molarity of an unknown NaOH solution if 25.00 mL of sodium hydroxide was titrated with 15.00 mL of a 1.500 M sulfuric acid solution (H2SO4). (aOH -40.00 g/mol and H2SO=98.08 g/mol) (10pts) 2NaOH(aq) + H2SO4(aq) + Na2SO4(aq) + 2H2O

1) A flask containing 450.0 mL of 0.500 M HBr was spilled on the floor. How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following reaction?

2 HBr (aq) + K2CO3 (s) => 2KBr (aq) + H2O (l)

2) Determine the molarity of an unknown NaOH solution if 25.00 mL of sodium hydroxide was titrated with 15.00 mL of a 1.500 M sulfiric acid solution (H2SO4). (aOH= 40.00 g/mol and H2SO4 = 98.08 g/mol)

2NaOH(aq) + H2SO4(aq) => Na2SO4(aq) + 2H2O

Answer 1

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17 Given that 450.ml of 0.5M HBr Weight of ko co im gon = ? . Froom Gram - equivalent Rule applys ... gm-eq of HBr = gm-eq of K₂ Coz NHB X Y H B = kleight of K2CO3 Equivalent weight of Ke CO 1X0.5X450 - wight of K₂CO3 Ia-factor of koca 138 or weight of Kg CO2 = 0.54450 x 138 = 15.52591 1000 138 15.5 2.) Molority of Unknown NaOH=? volume of NaOH = 25m 1 For Hasoy » volume = 15 ml, Molaritys 105M gm-equivalent Ni XVI of Hasoy = gm-equivalent of Naoh = N₂ X V₂ | My = Normality of M, X x-factos XV, = M2 XX-factor x 2 - H₂S, M = vol. of Hase, |N2 = Normality of - NaOH 1 m2 = vol of NaOH | M, = Molasity of 1.582 X 15 1000 - Max 1 x 25 Tooo Hasoy ou M2 = 105x2x15 1.8M My = Molasity of 25 NaoH Molasity of NaOH = 1.8m