Question

1. Determine the volume (mL) of 0.400 M H2SO4 acid required to react completely with 128.0 mL of 0.525 M NaOH base solution. Ans: 82.0 mL H2SO4 (aq) + 2NaOH (aq) → Na2SO4 (aq) + 2H20 (1)

Answer 1

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Ginen, M = molarity of H, sou = 0.400M V = volume of H₂ sou = ? M2 = Molarity of Naon: 0.525M V2: Volume of NaOH = 128.0 mL. Moles of H₂SO₄ = M. V moles of Naon = M₂ Neutralisation reaction of H₂sou and Naon us as M250,129.) + 2Naon (@7.) → NG, S0, C6g.) 421,0111 By looking at stochiomety of above reaction I mole of 1. soy reacts with 2 mole of NaOH. " M, xv, mole of 11₂ sou reacts with 2x M, xv, moles of Naon i moles of Noon= ax M, xv, Also, moles of Naon = M2 X V2 i M₂ x ₂ = 2X M, V or v = M, X V2 Putting values an above eg we get Vie 0.525M X 128.0ml 2 X 0.400 M uhon calculations we get 1984.0mL i volume of H₂ sou required : 84.0mL Scammed with CamScanner