What volume of 0.259 M H2SO4 is needed to react with 47.1 mL of 0.116 M NaOH? The equation is
H2SO4(aq)+2NaOH(aq)→Na2SO4(aq)+2H2O(l)
using the dilution law M1V1 / n1 = M2V2 / n2
here M1& M2 are molarities
V1&V2 are volumes
n1 & n2 are no of moles
H2SO4 + 2 NaOH ------------------> Na2SO4 + 2 H2O
for H2SO4 => M1 - 0.259 M , V1 - ? , n1 - 1
for NaOH => M2 - 0.116 M , V2 - 47.1mL , n2 - 2
M1V1 / n1 = M2V2 / n2
V1 = M2V2n1 / n2M1
V1 = 0.116 * 0.0471 L * 1 / 2*0.259
V1 = 0.010547 L
V1 = 10.55 mL
answer => 10.55 mL
What volume of 0.259 M H2SO4 is needed to react with 47.1 mL of 0.116 M...
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