Question

Fig. 1. Logic circuit for Question 1 2. The 60 W light bulb shown in Fig. 2 is rated at 120 volts. Calculate the required supply voltage V, to make the light bulb operate at the rated conditions. (2 pts) 50 22 Bulb 3 802 Fig.2. Circuit for Question 2 (3 pts) 3. For the circuit shown in Fig. 3, using KVL & KCL: a. Determine the currents i1, 12 & 13 b. The voltage across the resistor R1, R2 and R3 c. The power dissipated in the resistors R1, R2 and R3 V = 60 V ( 1 V, = 20 V + R = 20 R= 102 Fig.3. Circuit for Question 3

Answer 1

Power : 60W . Voltage = 1200 - 'PEVI .. . - I P V 120 We know V=IR . -). REV. 120 0.5 0.5 A 20 20 = 240 2 sor a < 80 v 240 (t bulb D . 1. For the bulb to operate at rated Conditions, Vm = 120v. 240 2 & 8or are in parallel making a equivalent of con sor RA Vs } bor VA = 120V =) VA = Vsx60 50+60 =) Vs = zóxllo = 290 V

. 1 R₂ § 52 Vi lov vigov @ R5 Roar Rzelor , Apply Kel at a - 60 - VX-20 + + 5 (Vx-60) + Vx-20+ 9 Vx=0 =) - Vr = 320 Vm40 V - 2 i 60-40 = 10 A iz - 20-40 = -2 A lo iz - 40-0 - BA Vaz i Ri - 10 (2) = 20 V Var iz Ry = -2(10) = -20 v Vez - 3 R3 = 8(5).= 40 v. Power dissipated across. a) Ri - Vrii20110) = 200 W 6) R2 = Naziz = -20 (-2) = 40 W c) Rz Voz iz : 4018) - 320 W