Question

2. A 5 kg block sits at rest on an inclined ramp which makes an angle of 24 degrees with respect to the horizontal. It is noted that even if the angle 0 is increased the block still does not slip. The coefficient of static friction for the bottom surface of the block and the surface of the ramp is us= 0.56. The magnitude of the frictional force acting on the block must be O 1 O O A. 50 N O B. 45 N o C. 40 N O D. 35 N E. 30 N O F. 27 N. O G. 25 N O H. 20 N O I. 15 N. O J. 10 N. O

Answer 1

here,

mass of block , m = 5 kg

angle of inclination , theta = 24 degre

as the block is at rest

the frictional force , ff = applied force

ff = m * g * sin(theta)

ff = 5 * 9.81 * sin(24) N

ff = 20 N

the frictional force is H) 20 N