Determine the energy needed to change a 0.35 kg block of ice at 0 ∘C into...
Determine the energy needed to change a 0.35 kg block of ice at 0 ∘C into water at 23 ∘C. The heat of fusion for water at 0 ∘C is Lf = 3.35×105J/kg. The specific heat of water is c = 4180 J/kg⋅∘C.
Homework Answers
Heat required, Q = m[Lf,ice + CwΔT]
=> Q = 0.35 * {(3.35 * 105) + [4180 * (23 - 0)] } = 150899 J
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