A signal has a period T of 0.014 µs, state it's frequency (showing formula)
A signal has a period T of 0.014 µs, state it's frequency (showing formula)
Homework Answers
A signal has a period T of 0.014 µs; T=0.014 * 10-6 sec
The formula for frequency is: f (frequency) = 1 / T (period)
So, f (frequency) = 1/(0.014 * 10-6) = 71.42 * 106 Hz
Hence A signal has a period T of 0.014 µs, frequency would be (71.42 * 106 )Hz.
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A signal has a period T of 0.014 µs, state it's
frequency (showing formula)
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Fundamental Frequency of Continuous Signals To identify the period T, the frequencyf= 1/T, or the angular frequency ω = 2nf= 2m/T of a given sinusoidal or complex exponential signal, it is always helpful to write it in any of the following forms: sin (gd-sin(2nf)-sin(2t/T) The fundamental frequency of a signal is the greatest common divisor (GCD) of all the frequency components contained in a signal, and, equivalently, the fundamental period is the least common multiple (LCM) of all individual periods...
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Consider the sawtooth signal y(t) whose period
is {T} microseconds. Within each period, the signal rises from 0
volts to 3.5 volts.
This signal has a Polar Fourier Series
What is the value of C0? Answer will be in
volts.
Ey(t) = o Ce cos(kwot+0k), where we = 25*10
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