Here, block size is 16 bytes so, last digit is used for offset. i.e last 4 bits are used for block offset
first 3 digit will decide where the block will be loaded in cache .
content of cache is shown below after each request.
if you have any doubts, you
can ask in comment section.
Assume you have a 4 entry fully associative cache that holds 16 bytes/block. The cache uses...
Assume a 16-way set associative cache that holds 4096 bytes, where each block is 16 bytes. Assuming an address is 32 bits and that cache is initially empty complete the table below. (You should use hexadecimal numbers for all answers.) Address TAG Cache location (block) | Offset within block OxOFFOFABA 0x00000011 0xOFFFFFFE 0x23456719 OxCAFEBABE Which, if any of the addresses will cause a collision (forcing the block that was just brought in to be overwritten) if they are accessed one...
1. A cache holds 64 words where each word is 4 bytes. Assume a 32 bit address. There are four different caches a. A direct-mapped cache with block size = 16 words b. 2-way set-associative cache with block size = 8 words c. 4-way set-associative cache with block size=4 words d. A fully associative cache with block size = 16 words. Complete the table for each cache. Cache a Cache be Cache Cache de 16 Number of bits needed for...
Assume a memory model where you have a cache size of 4 blocks, a block size of 8, and addresses from 0 through 511. Assume that the n-way associative cache and fully associative cache use a LRU (least recently used) eviction strategy. Consider the following sequence of memory accesses: 17, 66, 22, 66, 80, 41, 85, 66, 17, 104. (a) Show the updates to a 2-way associative cache in a table using a similar format to the table shown on...
Suppose a computer using fully-associative cache has 222 words of main memory and a cache of 32 blocks, where each cache block contains 16 bytes. How many blocks of main memory are there? Assuming memory addressing starts from zero, what is the highest memory address? How many bits are needed to represent all of the memory addresses? What is the format of a memory address as seen by the cache, that is, what are the sizes of the tag and...
Suppose we have a byte-addressable computer with a cache that holds 8 blocks of 4 bytes each. Assuming that each memory address has 8 bits and cache is originally empty, for the cache mapping technique, two-way set associative, trace how cache is used when a program accesses the following series of addresses in order: 0x01, 0x04, 0x09, 0x05, 0x14, 0x21, and 0x01.
32 bytes of memory. 16 bytes of 2-way set-associative cache, where blocks can go anywhere within the set. Block is 2 bytes, set in cache is two blocks. Populate memory starting with upper-case letters, then 0-5. Hint- with full associativity in the set: each block has its own set of Tag bits in the cache. Memory is not organized by sets, though blocks get assigned to sets, and load in the cache per set. 1) Break down the addressing: Tag...
Suppose a computer using a fully associative cache has 232 bytes of byte-addressable main memory and a cache of 1024 blocks, were each cache block contains 32 bytes. Consider a memory address as seen by the cache. How many bits are in the tag field?
3. (12 points) Consider a cache has lines of 16 bytes and a total size of 16 kB. The main memory is 16MB and a word takes 4 bytes. For the hexadecimal main memory addresses FFF666, show the following information in hexadecimal format a. Tag and word values for associative cache b. Tag, set and word values for a two-way set-associative cache
3. (12 points) Consider a cache has lines of 16 bytes and a total size of 16 kB....
Consider a direct-mapped cache with 32 blocks Cache is initially empty, Block size = 16 bytes The following memory addresses (in hexadecimal) are referenced: 0x2B4, 0x2B8, 0x2BC, 0x3E8, 0x3EC,0x4F0, 0x8F4, 0x8F8, 0x8FC. Map addresses to cache blocks and indicate whether hit or miss
Cache question computer architecture A cache holds 128 words where each word is 4 bytes. Assuming a 32-bit address, for each of the following organizations, complete the table. a.A direct-mapped cache with block size = 16words b.2-way set-associative cache with block size = 8words c.4-way set-associative cache with block size = 4words d.A fully associative cache with block size = 2words. Cache a Cache b Cache c Cache d total # bits for word & byte displacement # bits in...