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Q.1 The shown system is a balanced 3 phase double circuit which is appropriately transposed. a) Calculate L and C per phase i

Power systems

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Answer #1

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(a) LÓ 8m Dab? 6m 0 Daa 6m 0

(a) Self-distances: Daa = V122 +82 = 14.422m Dbb = 8m Dcc = Daa = 14.422m Dsa = Daa * Daa * Daa * Daa= V0.7788 +0.015

Mutual Distance: Dab = 6m, Dab = Dab = V62 + 82 = 10m, Dab = 6m Dm1 = VDab * Dab* Dab* Dab = 7.746m Dbc = 10m (by sy

For Capacitance GMR is not considered (a) Self-distances: Daa = V122 +82 = 14.422m Dbb = 8m Dcc = Daa = 14.422m Dsa = DaaCapacitance: 2* Pire c= _1 9039 * 10-11 F/m Ds

(b)

S=0.2m S=0.2m a3 S=0.2m

For Inductance

GMR is considered (a) Self-distances: Dsal = Dsa2 = Dsa3; Ds = Dsal * Dsa2 * Dsa3 = Dsa1 Dsal = Vr* Dala3 * Dala2 = V0.015* 0

Self-Inductance Dm L = 2 * 10-7 * In = 0.4367uH/m DsFor Capacitance GMR is not considered (a) Self-distances: Dsa1 = Dsa2 = Dsa3; Ds = VDsa1 * Dsa2 + Dsa3 = Dsa1 Dsal = Vr* DalaMutual Distance: will be same as calculation of Inductance Dab = 6m, Da b = Dab = 162 + 82 = 10m, Dab = 6m Dm1 = VDab * D

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