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A 4.5 mH inductor is initially connected to a 5.9 V battery at t = 0...

A 4.5 mH inductor is initially connected to a 5.9 V battery at t = 0 through a 4.5 Ω resistor. Once the inductor is fully energized, the battery is removed and the 4.5 Ω resistor is connected between the two terminals of the inductor. Find the current flowing through the resistor 17.0 µsec after the inductor begins to be de-energized.

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Answer #1

Expression for the time constant for the LR circuit is given by 4.5x10-3 4.5 -1x10 sec Expression for the instantaneous volta

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