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(7) The equivalent circuit parameters of a single-phase 500 kVA. 2400 480 V, 50 Hz power Re-2000 , X 500 when referred to the

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table FORA given :- when reffer to Hvs Rc = 2000 n XM = soon Ri= 0.06 n R2=0.003 u X120.3 X2=0.012.1 500 KVA 24001480 V SO H2similarly Lvs to HVS RC= 2000 n s given Xm-soon 30, To find out original Rc fxm. REO 992 Re= Roox (N12 xm = Acox (NL) 2000 =Rea Xeq=0.6 JI Reep Xcea 4o.8 = 3·2 equins L- Hrs to Lvs Req=0.0054 U Xeq=0.024 Rcea Xeea 200on = 5000.) R2 = 0.06 m a X2 = 3het: Base value consides :- v-9400 V 500 KVA 500 KVA= VIXI! 208.33 and 500x10 3 = 11 2400 a base = 2400 208.33 Rpx - Req.pu =Raoontlu. Xeq=0.052 HVS to us N2 FE pe=0.277 V Xo 1-toa equivale similarly Lvs to Hus xeq=0.0020u Reqa 0.0004 6 for M 0.277 thet: Base value consides :- v-9400 V 500 KVA 500 KVA= VIXI! 208.33 and 500x10 3 = 11 2400 a base = 2400 208.33 Rpx - Req.pu =Repu= 80x208.37 = 6.guy ( d 24w Hrs to LVS R2 = 0.0052py X2=0.2004 RI=0.0052 pu X120.0260 PU ra K V2 X 5 1.73 pu re= Toeg 6.9R120.0002 pu R2=0.002 P9 X120001 py ум Xi = 0.00dpy q Rea 6.qu4 py VI SL ml 133 X2 12 T-eque Ri Ja 9 VI une Хо 3 RO given 50

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