Question

What are the units of k in the following rate law? Rate = k[x][y]^2 1/M s^2 1/M^2 s M^2 s M^2/s 1/M^3 s Given the following rate law, how does the rate of reaction change if the concentration of Y is doubled? Rate = k [X][Y]^2 the rate reaction will increase by a factor of 2 The rate of reaction will increase by a factor of 4. The rate of reaction will increase by a factor of 5. The rate of reaction will decrease by a factor of 2.The rate of reaction will remain unchanged.

Answer 1

6)
rate = k [X][Y]^2
put unit of all components except k,
M/s = k * M * M^2
M/s = k * M^3
k = M-2s-1
Answer: B

7)
order of Y is 2
so doubling Y will make rate 4 times
Answer: B

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