Choose the best answer below. Given the following rate law, how does the rate of reaction...
Choose the best answer below. Given the following rate law, how does the rate of reaction change if the concentration of X is halved and the concentration of Y is quadrupled?
Rate = k[X][Y]3
a The rate of reaction will increase by a factor of 4
b The rate of reaction will increase by a factor of 16
c The rate of reaction will remain unchanged
d The rate of reaction will increase by a factor of 32
e The rate of reaction will increase by a factor of 64
Homework Answers
Answer
d) The rate of reaction will increase by a factor of 32
Explanation
Rate = k[X][Y]3
If concentration of X is halved and concentration of Y is quadroubled
Rate = k ( [X]/2)(4 ×[Y])3
Rate = (1/2) × (4)3 k[X][Y]3
Rate = 32 × k[X][Y]3
Therefore,
Rate of reaction increased 32 fold
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