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Question 11 of 20 Un How much heat will be absorbed by a 95.9 g piece of aluminum (specific heat = 0.930 J/g.°C) as it change

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Answer #1

Heat absorbed(q) = ms(∆T)

q = 95.9×0.930×(67-23)

= 3924.2 J

Heat will be absorbed = 3924.2 J

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