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How much heat will be absorbed by a 72.3 g piece of aluminum (specific heat =...

How much heat will be absorbed by a 72.3 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature from 23.0°C to 67.0°C?

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Answer #1

The absorbed heat is calculated:

q = m * sh * ΔT = 72.3 g * 0.930 J / g * ° C * (67 - 23) ° C = 2958.5 J

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