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What is the standard Gibbs free energy of the reaction, H(aq) - H(aq)+F(aq), if its equilibrium constant at 298 Kis 7.2 10 A
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Answer #1

we have the relation: \Delta G = -RT lnK

Using the given values: \Delta G = -8.314 * 298 * ln(7.2 * 10-4) = +17.9 KJ/mol

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