The given equation is the acid dissociation equation of chloroacetic acid
ClCH2COOH + H2O <-----------> ClCH2COO- + H3O+
For this equilibrium the equilibrium constant is called dissociation constant denoted by Ka
Ka = [clCh2COO-][H3O+] /[ClCH2COO-][H2O]
As Pka is given and pKa = -log Ka
Ka (equilibrium constant) = 10-pKa
= 10-2.87 = 1.348x10-3
OPTION D
Chloroacetic acid (CICH2COOH) has a pka = 2.87 What is the value of the equilibrium constant...
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