The rate law for the mechanism below is A2(g) ⇌ 2A(g) K1, fast A(g) + B(g) ⇌...

Question

Question

The rate law for the mechanism below is
A₂(g) ⇌ 2A(g)   K₁, fast
A(g) + B(g) ⇌ AB(g)   K₂, fast
AB(g) + A(g) → A₂B(g)   k₃, slow

Options:

science chemistry

Answer 1

Answer #1

Rate of reaction is determined by slowest step of the reaction

As in the question third step is the slowest step

rate =k3 [A][AB]

Answer 2

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