Standard Gibbs free energy of this reaction, ΔGo = - 800.783 kJ/mol
Given that:
No.of moles of CH4 reacted = 2.43 moles
Therefore, Free change is given by:
ΔGorxn = (- 800.783 kJ/mol) x (2.43 mole)
ΔGorxn = -1945.9 kJ ------------- (Answer)
Use the References to access important values if needed for this question. Consider the reaction: CH4(g)...
Use the References to access important values if needed for this question. Consider the reaction 2CH.) + 70 (8) - 4CO2(g) + 6H2O(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.56 moles of CH @ react at standard conditions. AS surroundings J/K Submit Answer Retry Entire Group 9 more group attempts remaining
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17-free energy
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