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Use the References to access important values if needed for this question Using standard heats of formation, calculate the st
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Answer #1

Given:

Hof(NH4NO3(aq)) = -339.87 KJ/mol

Hof(N2O(g)) = 82.05 KJ/mol

Hof(H2O(l)) = -285.83 KJ/mol

Balanced chemical equation is:

NH4NO3(aq) ---> N2O(g) + 2 H2O(l)

ΔHo rxn = 1*Hof(N2O(g)) + 2*Hof(H2O(l)) - 1*Hof( NH4NO3(aq))

ΔHo rxn = 1*(82.05) + 2*(-285.83) - 1*(-339.87)

ΔHo rxn = -149.74 KJ

Answer: -149.74 KJ

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