Homework Answers
Given:
ΔHo rxn = -903.5 KJ/mol
Hof(NH3(g)) = -46.11 KJ/mol
Hof(N2O(g)) = 82.05 KJ/mol
Hof(N2(g)) = 0.0 KJ/mol
Balanced chemical equation is:
2 NH3(g) + 3 N2O(g) ---> 4 N2(g) + 3 H2O(g)
ΔHo rxn = 4*Hof(N2(g)) + 3*Hof(H2O(g)) - 2*Hof( NH3(g)) - 3*Hof(N2O(g))
-903.5 = 4*(0.0)+3*Hof(H2O(g)) - 2*(-46.11) - 3*(82.05)
Hof(H2O(g)) = -249.8567 KJ/mol
Answer: -249.86 KJ/mol
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