Question

Determine the activity in 61.0 mg of radium-226 (t_1/2 = 1.6×10³ yr) in becquerels.

Part 2   (1 point)

Determine the activity in 61.0 mg of radium-226 (t_1/2 = 1.6×10³ yr) in millicuries.

Answer 1

Giver, mass of radium (Ra) = 61 mg let> (W) part ) = 61X10-3 g Molar Mass (M) af (Ra) = 2.26 g/mol " Number of atoms of Ra (Not bej = W X NA (Avogadro's Number). (61810-3 ) x (6.022x1623) 226 N = 16251 x 1020 stems میرا نام ..0.693 U) Rate constant = Eys Chalf life) (54) Half life = 1.68103 years. V=> ty=[1.6x103)x( 3.16x109) J seconds (AS, 1 year = 3.168 107 Seconds *. Activity (A) = AN x (1.625x1020) A = 0.693 1.6 X 10" X 3.16 X10 =) A = 2.23x109 disintegration or vanno decay per seconds

A = 2.23x109 dps As, a des = 1 Becquerel (Bq) . Activity = 20 23x10.9 Becquerel Answer Part 2 millicurie 1 Bq = 2.7 X 100 o. 1.89x109 B9 = (2,7x10-8) x (2:23 X 10%) Activity = 60.13 milli curie Answer
2.23*10^9 Becquerels and 60.13 millicuries...ANSWER.