Question

Enter your answer in the provided box. What is the pH of 0.60 M ethanolamine, HOCH,CH_NH,, (K) = 3.2 x 10-5)? pH =

Answer 1

Making ICE table- HOCH₂ CH₂NH₂ + H₂O. HO-CH₂CH₂NH₂ + oH 0.60M - x 0.60-x ko - TH2 CH₂ CH₃NH2] [ori] (x)(x) (0.60-x) = 3.28165 [HOCH₂ CH₂NH₂) Since value of kb is very less, therefore, we can take- 0.60-x n0.60 22 = 3 .2 0.60 x= 4.38 x 102 Thus, [OH) = x = 4.38 x 102 . pOH = -log[Ort] = -log (4.38x102) = 1.36 and pH = 14 - POH = 14 - 1.36 = 12.64 Please Rate....