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Part A For the equilibrium of the dissociation reaction of the compound Az, the concentrations were found to be [A2] = 0.03

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Answer #1

In order to solve this question, we can use the following equation:

AG = -RT Ink eg

where, R = 8.314 JK-1mol-1

Given temperature = 273.15 + 25 = 298.15 K

and from the given concentration of species at equilibrium we can ascertain the value of Keq

(A2)

0.152 Reg = A eq = 0.703 0.032

Now, putting all the values into the equation for gibbs free energy,

AG = -8.314J K-Imol-1 x 298.15K X In(0.703)

AG = +873.3 J mol-1 ~ +873 J mol-1

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