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(c) (Challenging). 1.3608 g of sodium acetate trihydrate solid C2H3NaO2●3H2O (NaAc●3H2O, MM = 136.08 g/mol) was...

(c) (Challenging). 1.3608 g of sodium acetate trihydrate solid C2H3NaO2●3H2O (NaAc●3H2O, MM = 136.08 g/mol) was fully dissolved in 100.0 mL of pure water. What was the pH of this solution?

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Here is the solution of your question. If you have any doubt or need any clarification please comment in comment box and will definitely resolve your query. If you find useful please upvote it. Thanks in advance.

first we calculate molarity of solution Molarity = mass of solute x l (M) molar mass VLL) molan M = 103608 yoxd - 136.08gr/mo

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(c) (Challenging). 1.3608 g of sodium acetate trihydrate solid C2H3NaO2●3H2O (NaAc●3H2O, MM = 136.08 g/mol) was...
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