Question

How many grams of dipotassium succinate trihydrate (K2C4H4O4·3H2O, MW = 248.32 g/mol) must be added to 650.0 mL of a 0.0420 M succinic acid solution to produce a pH of 5.867? Succinic acid has pKa values of 4.207 (pKa1) and 5.636 (pKa2).

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Answer #1

Desved pH of buffer 2 5.867 pkg of succinic acid = 5.636 Now, dipottasium succinate ic K₂ Cu Hu Oy and succinic acid (C ₂ H 6

moles of from mono succinate that can be founed available succinic acid a 2x0.0273 = 0.0546 mol For this polasium disuccinate

Molar mass of potassium disuccinate = 248.32 g/mol

Moles of potassium disuccinate required = 0.1202 mol

Mass of potassium disuccinate required

= 0.1202 mol*248.32g/mol

= 29.848 g

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