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10.00 grams of KH2PO4 (FW = 136.086 g/mol) are dissolved in 500 mL of deionized H2O....

10.00 grams of KH2PO4 (FW = 136.086 g/mol) are dissolved in 500 mL of deionized H2O. How many grams Na2HPO4 (FW = 141.96 g/mol) need to be dissolved to create a solution with a pH of 6.90? For H3PO4, pKa1 = 2.15 , pKa2 = 7.20, and pKa3 = 12.37.

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Let mass of mart Pay an gm. Nu of mol = Given mass. molar mass. Ma of moles of KH, Poy = - .0734 136.00 No. of moles of NahpoAccording to Handersons equation. ph= pk + log [Mat Pou] [kth Pou pH = 7.20 + log n/90.98 1468 6.9 .7. 20t log - . 1468X70.9thank you

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