Question

x A2AE3133): D ome a female (3) Calculation of Reactants. From the Experimental Procedure, you are required to calculate the amounts of hydrogen peroxide and cyclohexene that would have been required to conduct this reaction. Either type in an equation or explain in words how you calculated these amounts. Please complete all work in the text box below. (m) 0.0537 mole of 30% hydrogen peroxide. You need to calculate the mass (grams) of 30% H20, needed. NOTE that this is a mass ratio, so 30% by mass means that you have 30g of H.O. per 100g of solution. Do NOT use density! (b) 0.0122 mole of cyclohexene. You need to calculate the mass (grams) and volume (milliliters) of cyclohexene needed.

Answer 1

mol a) 0.0537 md of 307. Hydrogen peroxide (H202) molar man og H202 = 34.01. 301 H₂O2 means 30 g H₂O₂ in 100 g solution. (ma = given mass | molan mak) that means mol of H₂O2 = 3og = 0.882 mol 34.01 g molt - that means 0.882 mol of H₂O2 in 0.0537 mol of 4202 in loog solution 100 g 0.0527 mol sol 0.882 mol so To have - = 6.099 300 0.0537 mol, 6.09 g of 301 H₂O2 needed ne man needed = 6.09g o b 0.0122m01 og Cyclohexene man of cyclohexene = mol x molar mass - 0.0122 mot x 82.14 9 = 1.009 masg Cyclohexene = 1.009 Answer

density of Cyclohexene= 0.8112 mu volume of cyclohexene= = man density = 1.23 m . 1.oog 018118 ml? volume needed = 1.23m2 Ansora