According to the equation when one mole of N2 is reacted that will release 180.5 kilo joules of heat.
Moles of NO generated = 35 Moles
Moles of N2 reacted = 35 /2 = 17.5 Moles
Amount of heat required = 17.5 mol x 180.5 kJ /mol = 3158.8 kJ ~ 3160 kJ
Hence 35 moles of NO will require 3160 kJ of heat
Option B is correct answer
For the reaction N2(g) + O2(g) → 2 NO(g), AH° = 180.5 kJ. How much energy...
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Given the standard enthalpy changes for the following two reactions: (1) N2(g) + O2(g) +2NO(g) AH° = 181.8 kJ (2) N2(g) + 202(g)—>2NO2(g) AH° = 66.4 kJ what is the standard enthalpy change for the reaction: (3) 2NO(g) + O2(g) 2NO2(g) AH° = ? Submit Answer Try Another Version 2 item attempts remaining