Question

4. Consider the following reactions: Table 2. 2 CIO" (aq) + 4* (aq) + 2e → A ) + 2 H20() 2 CIO3(aq) +12 H(aq) + 10 - A ) + 6H2O() Cl() +2e" 20"(aq) 2 Co (aq) + 4H+ (aq) + 4 + 2 co(aq) + 2 H20(0) 2 Clo; (aq) + 4H* (aq) + 4e-2003(aq) + 2 H20) 2 C103(aq) + 4H+ (aq) + 4e - 2 C10(aq) + 2 H2O() E .163 E=147 E=136 E 1194 E=115 E2222 Construct a Latimer Diagram (fill in the electrode potentials) and determine each of the following Co- Clo c hoz — — — a. Which reactant(s) are stable in 1M acid? Answer(s): b. Which reactants are unstable in 1M acid? Identify the source of the instability Answer(s): c. The best oxidizing agent in the group. Answer: d. The best reducing agent in the group. Answer: e. The value of the equilibrium constant (at 25°C) for the following half-cell reaction Clo; (aq) + 8H(aq) + 8e-cr(aq) + 4H2009) K=???

Answer 1

2 Clo" (aq) + 4* (aq) + 2e → C12(8) + 2 H20(1) 2 Clog (aq) +12 H+ (aq) + 10 + Cl2(g) + 6H2000) Cl2(g) + 2 e + 2Cl(aq) 2 CIO (aq) + 4H+ (aq) + 4e + 2 C103(aq) + 2 H20() 2 Clo(aq) + 4H+ (aq) + 4e-2 coz (aq) + 2 H20 (0) 2 CO2 (aq) + 4H(aq) + 4e - 2 CIO" (aq) + 2 H2O(1) E: +1.63 E=+1.47 E = +1.36v E = +1.19 E = +1.15 E = ????

Sot from the given table, latimer Die grom is 22 1.190 150 1.63V 1.36V czu (104 (103 cloz co clo com - 1.471 . Here we have to find out a value. from the thermodynamics, we know that, man039 elections to the chosId, = -nf EcoFloor- og Eucz kcó ng 100%, > -18*1.47 --4x1.15-442-8 X 1.0. → 42- 16 X1-47 - 4x1.15- 2X163 az 14.7-4.6 - 3.26 → az 171 V. complete la timer Diagram is a 1.369 € A 41.63V cotch 0 +1.19u clog o t1.15V +171V y com - y cloTiSv 1.474,

ka in generally, th unstable species on the latimer diagram will have a lower standard potential to left them to the right (a) stable specics cloa, clog Iclod, clic in unstable specick's C10,0 smce, it has alles to the left them to the right (C) The best choice ng cagent we know that, highest positice Stomdard redeetim potentials are the best oxidizing agent: In the abace latimer diagram of cloo cloo t°= 1.711 is having highest asi tice E value. clogo is a good oridising agent. (d) In the same way as above, the lowest the standard reduction potential is a highest reducing agent a clone is a best reeducing agent in the group (e) Glen Ean. c e.+AH2O cla +847 + fe ne know that DG=-FE AG = - RTln keq. Here we thato find out But, frost ae hatte to find Req. pe of the reaction given.

* -nf Ecoalue = - FC Flora - F 6020-nft ilo:ledom -ne lo/la-ne Elzlue 3) -168 Pelalu = - 48 119 – 4X1.15-421.71-221-63 - 2* 1.36 4.767 4. 6+ 6.84.+3.26+ 9.72 16 e coilce = 22,46 = Elaqe/d® – 1. 386 V , OG = DF e --Riin kes y linkee NFE 8x96500 x 1.356 IS RT 8.314 x 298 → In kesa 431.87 - 431.87 » keq=et 187 → keq = 3.6 X10
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