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Part C If the volume of the reaction vessel in part (6) was 1.50 L, what amount of Bry (in moles) was formed during the first


Consider the following reaction: 2HBr(9) H2(g) + Brz(9)


Part B In the first 21.0 s of this reaction, the concentration of HBr dropped from 0 550 M to 0.459 M. Calculate the average
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Answer #1

part (B) :

rate = change in concentration / time interval

rate = (0.550-0.459) / 21.0

rate = 4.33 x 10^-3 M.s^-1

part(C) :

rate of formation of Br2 = 1/2 ( rate of decomposition of HBr )

rate of formation of Br2 = 1/2 ( 4.33 x 10^-3 ) M.s^-1

rate of formation of Br2 = 2.16 x 10^-3 M.s^-1

concentration of Br2 = 2.16 x 10^-3 M.s^-1 x 15 s = 3.24 x 10^-2 M

moles of Br2 = conc. x volume = 3.24 x 10^-2 M x 1.5 L = 4.86 x 10^-2 moles

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