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May i have help please?

The equivalence point in the titration of this weak acid is 50.80 ml. At 25,40 ml, the pH was measured to be 3.86. Calculate
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Answer #1

Hi there,

In the given figure they clearly mentioned at half-way to the equivalence point pH = pKa (dotted line and mentioning This pH = pKa) , this means at half-way point the concentration of weak acid = conjugate base, so that log[conjugate base / weak acid] term becomes zero in Henderson-Hasselbalch equation

pH = pKa + log[conjugate base / weak acid] = pka + 0 = pKa

pH = pKa

but Ka = 10^-pKa = 10^-pH = 10^-3.86 = 0.00013803842 = 1.38 x 10^-4

so Ka = 1.38 x 10^-4 (OR) simply in scientific notation 1.38E-04

Hope this helped you!

Thank You So Much!

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