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What is the minimum mass of calaverite (AuTe), a gold ore, from which 100. g of pure gold could be extracted? Be sure your an

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Answer #1

Hi there

Molar mass of AuTe2 is 452.1666 g/mol

one mole of AuTe2 produces one mole of Au (gold)

moles present in 100. g of pure gold = 100 g / 196.966569 g/mol = 0.5077 mol

0.5077 moles of AuTe2 can give 0.5077 moles of gold

so convert moles AuTe2 into mass AuTe2 by multiplying moles AuTe2 with molar mass of AuTe2

minimum mass of AuTe2 required to extract 100. g of pure gold = 0.5077 mol x 452.1666 g/mol = 229 g

Answer: 229 g

What is the minimum mass of calaverite (AuTe), a gold ore, from which 100. g of pure gold could be extracted? Be sure your an

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