HomeworkLib
Question

Sulphur trioxide decomposes at high temperature in a sealed container: 2 SO3(g) <--> 2 SO2(g) + O2(g). Initially, the vessel

how to solve this?

science   chemistry   
1 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

کر250 ره سره د 0.5 داں ہر + 0.3 -0.32 0.3 0.15 kp: [sol]²[ 02] [ روک - (0.3 )۶( 2.15) (0.2) . - 0.338

0 0
Add a comment
Answer #2

Sulphur trioxide decomposes at high temperature in a sealed container: 2 SO3(g) <--> 2 SO2(g) + O2(g). Initially, the vessel is charged at 1000 K with SO3(g) at a partial pressure of 0.500 atm. At equilibrium the SO3 partial pressure is 0.200 atm. Calculate the value of Kp at 1000 K to 3 decimal places.


Kp=0.225

source: books
answered by: raine
0 0
Add a comment
Answer #3

Sulphur trioxide decomposes at high temperature in a sealed container: 2 SO3(g) <--> 2 SO2(g) + O2(g). Initially, the vessel is charged at 1000 K with SO3(g) at a partial pressure of 0.500 atm. At equilibrium the SO3 partial pressure is 0.200 atm. Calculate the value of Kp at 1000 K to 3 decimal places.


Kp=0.225

source: chem book
answered by: Eurika Raine
0 1
Add a comment
Know the answer?
Add Answer to:
how to solve this? Sulphur trioxide decomposes at high temperature in a sealed container: 2 SO3(g)...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • 2) For the equilibrium: 2 SO3(g) <=> O2(g) + 2 SO2(g) Kp = 0.269 at 625...

    2) For the equilibrium: 2 SO3(g) <=> O2(g) + 2 SO2(g) Kp = 0.269 at 625 °C What is Ke at this temperature? Kp = Kc[RT]An R = 0.08206 L-atm/mol K

  • Help

    The gaswous compound BrCl decomposes at high temperature in a sealed container. 2BrCl(g) <--> Br2(g) + Cl2(g). Initially, the vessel is charged at 500 K with BrCl(g) at a partial pressure of 0.500 atm. At equilibrium, the BrCl(g) partial pressure is 0.040 atm. Calculate the value of Kp at 500 K.

  • At a certain temperature, 1.00 mole sulfur trioxide (SO3) is introduced into a 1.00 L container....

    At a certain temperature, 1.00 mole sulfur trioxide (SO3) is introduced into a 1.00 L container. The SO3 partially dissociates by the reaction: 2 SO3 (g) ↔ 2 SO2 (g) + O2 (g) If 0.300 moles O2 is present at equilibrium, what is the value of kc for this reaction?

  • 2) For the equilibrium: 2 SO3(g) <=> 02(g) + 2 SO2(g) Kp = 0.269 at 625...

    2) For the equilibrium: 2 SO3(g) <=> 02(g) + 2 SO2(g) Kp = 0.269 at 625 °C What is Ke at this temperature? Kp = K[R R = 0.08206 L-atm/mol K (5pts)

  • At a certain temperature K = 0.500 for the following reaction: SO3 (g) + NO (g)...

    At a certain temperature K = 0.500 for the following reaction: SO3 (g) + NO (g) ⇌ NO2 (g) + SO2 (g) If 0.200 mol of SO3 and 0.200 mol of NO are placed in a 2.000 L container and allowed to come to equilibrium, what will be the concentration of SO2?

  • 9. -10.1 points 0/4 Submissions Used Gaseous SO3 is placed in a closed container at 560...

    9. -10.1 points 0/4 Submissions Used Gaseous SO3 is placed in a closed container at 560 °C, where it partially decomposes to SO2 and 02: 2 503(9) = 2 502(9) + 1 02(9) At equilibrium it is found that p(SO3) = 0.006960 atm, P(SO2) = 0.006580 atm, and p(O2) = 0.004150 atm. What is the value of Kp at this temperature? Kp =

  • Sulfur trioxide is formed from sulfur dioxide and oxygen according to the reaction formula 2 SO2...

    Sulfur trioxide is formed from sulfur dioxide and oxygen according to the reaction formula 2 SO2 (g) + O2 (g) ⇌ 2 SO3 (g) with the equilibrium constant 2.5 × 1010 at the temperature 5.0 × 102 K. A reaction vessel with a volume of 0.25 L contains from start 0.030 moles of SO2 (g) and 0.050 moles of O2 (g). a) Calculate the partial pressure SO3 (g) after equilibrium is reached at 5.0 × 102 K. b) Will more...

  • Be sure to answer all parts. A) Nitrogen dioxide decomposes according to the reaction 2 NO2(g)...

    Be sure to answer all parts. A) Nitrogen dioxide decomposes according to the reaction 2 NO2(g) ⇌ 2 NO(g) + O2(g) where Kp = 4.48 × 10−13 at a certain temperature. If 0.85 atm of NO2 is added to a container and allowed to come to equilibrium, what are the equilibrium partial pressures of NO(g) and O2(g)?   ___atm O2 ___atm NO B) For the following reaction, Kp = 0.262 at 1000°C: C(s) + 2H2(g) ⇌ CH4(g) At equilibrium, the partial...

  • 1.   2 SO3(g) ⇄ 2 SO2(g) + O2(g)     Kp = 1.2× 10-5 0.60 atm of SO3...

    1.   2 SO3(g) ⇄ 2 SO2(g) + O2(g)     Kp = 1.2× 10-5 0.60 atm of SO3 and 0.30 atm of SO2are placed in a container and the system is allowed to reach equilibrium. Calculate the pressure of O2(g) at equilibrium.? 2. Find the pH of 0.68 M HCOOH(aq) given that its Ka = 1.8×10-4. 2 questions please answer both

  • Sulfur dioxide and oxygen react to form sulfur trioxide, like this: 2SO2(g)+O2(g)→2SO3(g) Also, a chemist finds...

    Sulfur dioxide and oxygen react to form sulfur trioxide, like this: 2SO2(g)+O2(g)→2SO3(g) Also, a chemist finds that at a certain temperature the equilibrium mixture of sulfur dioxide, oxygen, and sulfur trioxide has the following composition: Calculate the value of the equilibrium constant Kp for this reaction. Round your answer to 2 significant digits. compound pressure at equilibrium SO2 58.3 atm 02 84.7 atm SO3 66.3 atm

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT