Answer is B.
NaOH is a strong base and it deprotonate both Carboxylic acid and alcohol but NaHCO3 is weak base and it deprotonate only Carboxylic acid and not alcohol.
Lab 7: Question 2 Homework. Unanswered Why is aqueous NaHCO3 used for the initial extraction of...
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract the acidic components of the unknown mixture? O A Acids and bases afford salts that are water soluble in this experiment O B It moves the compounds of interest to the aqueous layer It enables selective extraction by reacting a weak base and a strong acid followed by reacting a strong base and weak acid, O D all of the above
Lab 7: Question 7 Homework – Unanswered Why would it be relatively challenging to separate I and Il via an acid-base extraction? O A Only one of these is soluble in organic solvents O B Both are relatively neutral O C Compound II is more polar
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in order to make it water soluble for extraction from an organic solvent? ♡ on olemas O A The anion derived from Il is too strong and reactive a base to remain stable under aqueous extraction conditions Protonation of amines to form ammonium salts affords a less reactive salt compared to the deprotonation product O C Both a and b are correct
Acetylation of ferrocene and column chromatography
Lab 4: Question 3 Homework • Unanswered Important ... The solvent is changed from petroleum ether to diethyl ether after the ferrocene is collected from the column. Why not use diethyl ether the entire time? Because diethyl ether is more polar than petroleum ether Because petroleum ether selectively elutes ferrocene since it contains more ether oxygens than diethyl ether Because diethyl ether would lead to a poorer separation of ferrocene and acetylferrocene Both a...
Question 2 of Prelab questionsWhy is the CH2Cl2 layer the bottom layer in a CH2Cl2 / aqueous NaHCO3 extraction? In this experiment, what does the CH2Cl2 layer contain? What does the aqueous NaHCO3 layer contain?
06 Lab 3a Separation.pdfQuestion 1 of prelabExplain in a few sentences how extraction can be used to separate an organic compound from sodium chloride.
Prelab
1. Explain in a few sentences how extraction can be used to separate an organic compound from
sodium chloride.
2. Why is the CH2Cl2 layer the bottom layer in a CH2Cl2 / aqueous NaHCO3 extraction? In this
experiment, what does the CH2Cl2 layer contain? What does the aqueous NaHCO3 layer
contain?
3. In general, how...
question 1 and 2!
CHE 129A Lab 5_Liquid-Liquid Extraction Name : Rika Mochizuki Date : _ 10/28/19 Notebook Ref: _Attached! Part 1: Simple Extraction and Determination of the Distribution Coefficient (Partition Coefficient) for Propionic Acid Between Ether and Water Table 1 (a) Preparation of Propionic Acid (PA) Solution weight PA Volume H2O (mL) (b) Titration of Aqueous Propionic Acid Solution Before Ether Extraction Volume PA Volume NaOH Aliquot (mL) (mL) 10.wml 18.00ml (c) Titration of Aqueous Propionic Solution After Ether...
Liquid-liquid extraction lab questions 1. Why does the m-nitroaniline dissolve in acid? 2. Why does the benzoic acid dissolve in base? 3. Why does the naphthalene remain in the organic layer? Please answer in details, thank u!