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![Now [Win a Won] H indicates that the amow of soluk extracturns is greatter for muthstep extraction method. Hence, multistep](http://img.homeworklib.com/questions/5ec59210-d455-11eb-ac11-21dbe62b2266.png?x-oss-process=image/resize,w_560)
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Lab 7: Question 1 Homework. Unanswered Which is generally more efficient, extracting an organic layer using...
Lab 7: Question 7 Homework – Unanswered Why would it be relatively challenging to separate I...
Lab 7: Question 7 Homework – Unanswered Why would it be relatively challenging to separate I and Il via an acid-base extraction? O A Only one of these is soluble in organic solvents O B Both are relatively neutral O C Compound II is more polar
Acetylation of ferrocene and column chromatography Lab 4: Question 3 Homework • Unanswered Important ... The...
Acetylation of ferrocene and column chromatography
Lab 4: Question 3 Homework • Unanswered Important ... The solvent is changed from petroleum ether to diethyl ether after the ferrocene is collected from the column. Why not use diethyl ether the entire time? Because diethyl ether is more polar than petroleum ether Because petroleum ether selectively elutes ferrocene since it contains more ether oxygens than diethyl ether Because diethyl ether would lead to a poorer separation of ferrocene and acetylferrocene Both a...
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract...
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract the acidic components of the unknown mixture? O A Acids and bases afford salts that are water soluble in this experiment O B It moves the compounds of interest to the aqueous layer It enables selective extraction by reacting a weak base and a strong acid followed by reacting a strong base and weak acid, O D all of the above
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in...
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in order to make it water soluble for extraction from an organic solvent? ♡ on olemas O A The anion derived from Il is too strong and reactive a base to remain stable under aqueous extraction conditions Protonation of amines to form ammonium salts affords a less reactive salt compared to the deprotonation product O C Both a and b are correct
What is the purpose of extracting the aqueous layer two more times with ether in step...
What is the purpose of extracting the aqueous layer two more
times with ether in step 5?
What is the purpose of washing the combined organic layers with
NaOH in step 6?
Thank you
Reaction 1: Nitration HNO3 NO2 + H2SO4, H20 NO2 toluene NO2 ortho meta para Procedure for Reaction 1: 1) To a stirred solution of 3 ml (44.7 mmoles) 67 % HNO3 in 3.75 mL of water, H2SO4 (9 mL) was slowly added at 10-15 °C. 2)...
pre-laboratory Questions A 1 Explain why it is more efficient to make several extractions using small...
pre-laboratory Questions A 1 Explain why it is more efficient to make several extractions using small portions rather than one extraction using the same total volume. 2 Define the following terms: Drying agent intensity Drying agent capacity 3 Select the upper layer in each pair of mixed solvents (see Appendix C): Water and benzene Water and carbon tetrachloride Water and ether 4 Write an equation for the reaction of a benzoic acid with aqueous sodium bicarbonate. 5 Complete the following...
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in...
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in...
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 5 Homework – Unanswered How would one separate each of I, II and...
Lab 7: Question 5 Homework – Unanswered How would one separate each of I, II and Ill when dissolved together in diethyl ether? СА Add a weak base in water to extract the salt of III, then add a strong base in water to the diethyl ether to extract the salt of II B O Add a weak h Add a weak base in water to extract the salt of II, then add a strong base in water to the...
LTE Data Link Homework. Unanswered Match the LTE Data Link layer protocol with its description Drag...
LTE Data Link Homework. Unanswered Match the LTE Data Link layer protocol with its description Drag and drop options on the right-hand side and submit. For keyboard navigation... Show More Packet Data Convergence fragmentation and reassembly, reliable data transfer Radio Link Control III use of radio transmission slots Medium Access III mobility management III header compression and encryption III authentication services Unanswered Submit Multiple Correspondents Homework. Unanswered Which issues effect multiple concurrent correspondents Select an answer and submit. For keyboard...
Lab 7: Question 7 Homework – Unanswered Why would it be relatively challenging to separate I and Il via an acid-base extraction? O A Only one of these is soluble in organic solvents O B Both are relatively neutral O C Compound II is more polar
Acetylation of ferrocene and column chromatography
Lab 4: Question 3 Homework • Unanswered Important ... The solvent is changed from petroleum ether to diethyl ether after the ferrocene is collected from the column. Why not use diethyl ether the entire time? Because diethyl ether is more polar than petroleum ether Because petroleum ether selectively elutes ferrocene since it contains more ether oxygens than diethyl ether Because diethyl ether would lead to a poorer separation of ferrocene and acetylferrocene Both a...
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract the acidic components of the unknown mixture? O A Acids and bases afford salts that are water soluble in this experiment O B It moves the compounds of interest to the aqueous layer It enables selective extraction by reacting a weak base and a strong acid followed by reacting a strong base and weak acid, O D all of the above
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in order to make it water soluble for extraction from an organic solvent? ♡ on olemas O A The anion derived from Il is too strong and reactive a base to remain stable under aqueous extraction conditions Protonation of amines to form ammonium salts affords a less reactive salt compared to the deprotonation product O C Both a and b are correct
What is the purpose of extracting the aqueous layer two more
times with ether in step 5?
What is the purpose of washing the combined organic layers with
NaOH in step 6?
Thank you
Reaction 1: Nitration HNO3 NO2 + H2SO4, H20 NO2 toluene NO2 ortho meta para Procedure for Reaction 1: 1) To a stirred solution of 3 ml (44.7 mmoles) 67 % HNO3 in 3.75 mL of water, H2SO4 (9 mL) was slowly added at 10-15 °C. 2)...
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 5 Homework – Unanswered How would one separate each of I, II and Ill when dissolved together in diethyl ether? СА Add a weak base in water to extract the salt of III, then add a strong base in water to the diethyl ether to extract the salt of II B O Add a weak h Add a weak base in water to extract the salt of II, then add a strong base in water to the...
LTE Data Link Homework. Unanswered Match the LTE Data Link layer protocol with its description Drag and drop options on the right-hand side and submit. For keyboard navigation... Show More Packet Data Convergence fragmentation and reassembly, reliable data transfer Radio Link Control III use of radio transmission slots Medium Access III mobility management III header compression and encryption III authentication services Unanswered Submit Multiple Correspondents Homework. Unanswered Which issues effect multiple concurrent correspondents Select an answer and submit. For keyboard...
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