Question

stion 4 How many grams of O2 will be consumed during the formation of 13.5 grams of Fe2O3? Report your answer with 3 significant figures, Molar mass of Fe203 - 159.69 g/mol 4 Fe +3 02 - 2 Fe203

Answer 1

I solution:- reaction:- u Fe + 302 & 2 Fe2O₃ I First calculate no. of moles of formed. so Fe2O3 mass of Fe2O3 molar mass of form = 13.5 grams Fe2O₃ = 159.69 g/mol So, no, of moles of fez Oz : ? 13.5% = 0.08454 mel 159.69 g/mol According to the reaction 2 mol of Fe₂O3 formed by 3 mol of a 30, 0.08454-mol of Fe₂O3 formed by Largo ( 3 x 0. 0845 4 Imol of Our = 0.12681 mol of O₂ molar mass of O2 = 32 g/mol grams of Oz consumed - no. of moles of O₂ consumed x molar mass of O2 - 0.12 681 mol X 32 g/mol = 14.06g of O₂ consumed

4. Об ата мд 9, 0, u | Соли мо о during the formation of 13.5 g Fe₂O3. of