4Fe(OH)^+ (aq) +4(OH)^-(aq) + O2 (g) +2H2O(l)---> 4Fe(OH)3
How many grams of O2 are consumed to precipitate all of the iron in 80.0 mL of 0.0450 M Fe(II)?
I dont understand how to even go about answering this question, so please simplify it as much as possible.
4Fe(OH)^+ (aq) +4(OH)^-(aq) + O2 (g) +2H2O(l)---> 4Fe(OH)3 How many grams of O2 are consumed to...
Fe(II) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fe(II) to insoluble Fe(III): 4Fe(OH)+ (aq) + 4OH- (aq) + O2 (g) + 2H2O (l) -----> 4Fe(OH)3 (s) How many grams of O2 are consumed to precipitate all of the iron in 60.0 mL of 0.0450 M Fe(II)? ____g
Feedback See Periodic Table Fe(II) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fe(ll) to insoluble Fe(III): 4Fe(OH(aq) +40H (aq) +0,(8) + 2H,00) — 4Fe(OH), ) How many grams of O2 are consumed to precipitate all of the iron in 60.0 mL of 0.0850 MFeClu? 32 1st attempt
3rd attempt See Periodic Table See Hint Fe(I) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fe(I) to insoluble Fe(II): 4Fe (OH) (aq)40H (aq) +0,(g) +2H,0(1) » 4Fe (OH)2(s) How many grams of O2 are consumed to precipitate all of the iron in 55.0 mL of 0.0950 MFe(II)? 2nd attempt <13/27 4 VIEW SOLUTION 18 OF 27 QUESTIONS COMPLETED SUBMIT ANSWER
Fe(lI) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fel1) to insoluble FelllI) 4Fe(OH) (ag)+40H (ag)+02()+2H200)4Fe(H)3(s) How many grams of O2 are consumed to precipitate all of the iron in 500 mL of OOS 50 M Fe(II)?
See Periodic Table SeeH Fe(ll) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fein to insoluble Fe(lll): 4Fe(OH)*(aq) + 4OH(aq) +0,(8) +2H,0(1) 4Fe(OH),() How many grams of O, are consumed to precipitate all of the iron in 60.0 ml of 0.0850 Mrel)?
stion 4 How many grams of O2 will be consumed during the formation of 13.5 grams of Fe2O3? Report your answer with 3 significant figures, Molar mass of Fe203 - 159.69 g/mol 4 Fe +3 02 - 2 Fe203
Fe(s)+O2(g)+H2O(l)=Fe(OH)3(s) A) Balance the equation. B) A 27.9-gram iron nail falls into a stream and remains at the bottom rusting for many years. Eventually all the iron reacts to form rust. How many grams of rust form?
determine how many grams of the precipitate will be for produced if 75.0 g of iron (ii) nitrate completely react with excess sodium sulfate first balance out the equation and show work. __Fe(No3)2(s) + __Na2S(aq) > __FeS(s) + ___NaNo3(aq)
for the reaction 2CL2(g)+4NaOH(aq)-> 3NaCl(aq)+NACIO2(aq)+ 2H2O(1) how many grams of NaCl can be produced from 67.5g of Cl2 and excess NaOH
Calcium hydride (CaH2) reacts with water to form hydrogen gas: CaH2(s) + 2H2O(l) → Ca(OH)2(aq) + 2H2(g) How many grams of CaH2 are needed to generate 45.0 L of H2 gas at a pressure of 0.888 atm and a temperature of 32 °C?