Question

2. There are different gases in three connected, but separate containers, under the conditions given below. If the gases are allowed to mix and the final volume of the container is 3.0 L, what is the partial pressure of the He in the mixture? (The temperature remains at 298 K.) What is given? What do you want to know? What else do you need to know? Solve the problem: Continue to next page He Ar N2 Volume 1.5L 0.5L 1.0L Pressure 0.5atm 2.0atm 1.0atm Temperature 298K 298K 298K

Answer 1

Ar Before mixing I V2=0.5L V - 1.5L I V = 1.0L TP2 = 2atm P = 0.5 atm 112 = 1 am T = T2 = I3 = 298k (Same ) Mole of He, n = P. vi - 0.5 1.5 RT 0.082 x 298 -0.03069 mole After mixing mole of He is still constant only change in volume and Pressure / Partial Pression New Volume The V= Via V₂ + V₂ = 32 than partial Pressure of He is PHe v = h, RT Pue = H, RT = 0.03069 X 0.082 x 298 I Phe = 0.2499 atm