Question

Equivalence Point - this is the point where the moles of the titrant are equal to the moles of titrated solution 25ml. 0.10M HNO, with 0.10M KOH 25ml 0.10M CH,COOH with 0.10M NaOH 25ml 0.10M NH, with 0.10M HCI Weak Base /Strong Acid What volume of strong acid is needed to reach the equivalence point? Determine the final concentrations (molarity) after the addition of this much acid. "Remember The total volume will have changed Moles before Change Moles after Final Molarity (mol/L)* Calculate the resulting pH. Use what is leftover to determine how to proceed, brid or have any left at all → comnlete dissariatinn Inn ICE table neered

Answer 1

aud For weak Base / Strong, ritration pe 25ml of 0.1M NH with 0.1 M He NҢ он a strong acid (weak Bares Ab equivalence prêt, milling of Base (Ntty OH) = melles 25x0.11 7 auel HCO 0.1% Vue Ice Vice a 25 me] (NH4OH)/C01%) = 20. 26X1. OLM - 25 Xool . 25+25 25 Xool OT 2 Dolm Soa 2 final tricentration 1 [nce final concentration final encentration 2 258ool . - 25+25 OP 2510il. so la olm.

NH,OH + Hoy from the Nhy Attro 2.5 mmoles 2.5 mmoles (Inctial) = 2.58103 moles 22,5X10 moles + Ho, keq = (KINH, Kw Dinociation Change 1 - 2.58153 moles Custand of -2.50153 moles water moleso after 2.5X15' moles final concentration am am M 2258103 moles 50x103 of m-a 2011 [Nry ] . lofxlos 1514 [H® ] [ ai toport] Kilometer Oude , 1187/39 15 w 421,88%-5 aliothes (Not given in question though) 2 x2 ol X10-92 xh 2 X 1.8 0.0277*79.42 (HO)2 xo 10-277x10 to 2 0.526 x 10-5 M pha -log[4") = -log(0.426815-5) S28 pH at equivalence poribe