Question

13) Chemical Formula: C11H1403 IR: strong peak 1720cm-1, strong broad 3300cm-1, 2H Зн Зн 1н 1н1н 1н 1н/ 1н 9 8 8 7 PPM 14) Chemical Formula: CnH240 IR: strong peak 1720cm-1, strong broad 3300cm-1 ЗН Зн 2H 2H 1Н 1н PPM

Answer 1

1) C11H1403 Degree of unsaturation = ((2C+2)+N-H-X)/2 = (24-14)/2 = 5 The compound contains di substituted benzene ring as there are 4 aromatic protons. IR: 1720: C=O stretching 3300: borad COOH a: 1.5ppm: 3H, d: CH3-CH b: 3.2ppm: 3H, S: CH3-Ar C: 4.7ppm: 1H, q: X-CH-CH3 d: 4.8ppm: 2H, S: X-CH2-Ar e: 4.9ppm: 1H, bs: -OH may be from COOH f: 7.4ppm: 1H, dd: ortho/ortho coupling g: 7.5ppm: 1H, d: ortho coupling h: 7.8ppm: 1H, d: meta coupling i: 8. Oppm: 1H, d: ortho coupling cohe CH3 a fVCH3 The possible structure is: 2-[(3-methylphenyl)methoxy]propanoic acid

14) C11H1403: Degree of unsaturation = ((2C+2)+N-H-X)/2 = (24-14)/2 = 5 The compound contains di substituted benzene ring as there are 4 aromatic protons. IR: 1720: C=O stretching 3300: borad COOH a: 1.5ppm: 3H, d: CH3-CH b: 3.2ppm: 3H, S: CH3-Ar ç ohe C: 4.7ppm: 1H, q: X-CH-CH3 d: 4.8ppm: 2H, S: X-CH2-Ar e: 4.9ppm: 1H, bs: -OH may be from COOH f: 6.8ppm: 2H, d: ortho/ortho coupling g: 7.2 ppm: 2H, d: ortho/ortho coupling Thus it is para di substituted ring. The possible structure is: CH3 a