Question

According to the following reaction, how many grams of dichloromethane (CH2CH) will be formed upon the complete reaction of 23.9 grams of carbon tetrachloride with excess methane (CH) ? methane (CH)(8) + carbon tetrachloride(g) - dichloromethane (CH2Cl() grams dichloromethane (CH,CI») Submit Answer

Answer 1

ot cely Solution CH4c9) + caly cg) — 2CH2 42 (9) dichloromethane mo. of moles (n) = ginen Mass = 23.99 - Molar Mass 153.82g/mol = 0.1553 mol of - cely Imole of eta cely forms - 2 moles of CH₂ C 0.1553 mole " " - 2X0.1553 mole 1 of CH₂U, = 0.3106 mole of for CH₂Cl₂ 1 CH₂ CU no. of moles = given Mass Molar Mass graus of Chall, = 0.3106 X 84.93 g/mol. = 26.37.91 Answey = NH, NO, (+) – N, 4 ) +2H2O (4) . no. of males of = 26.2g = 0.40 moles of NH y NO - NHUNO .. 64.86 g/mol According to the reaction. - I mole of NHuNo, produces I mole of N₂ gal. so 0.40 " " " 0.40. moles ". n = (Mass) N2 = Muss = 0,40 mole X 28 g/m Mus = (11271 Answey two )

= sifarsit 2420 11 . moles of H₂O = 32.79 4 H F G + SiO₂ (s) = 1081 mol A 18 g/mol = . 2. moles of H₂o produces u moles of Hf lo8l " " " - 4 x 1.81 moles of Hf (Mass) oef = (ou.Mass) HEX NHA = 3.62 moles of He = 20 g/mel x 3.62 mol = 12,4 g of He Auswah z VALVES