Ester= Isoamyl acetate (banana)
Molar mass of banana= 130.19
density= 0.876 g/ml
5.26 g ester product.
Alcohol= isoamyl alcohol
density= 0.81 g/ml
Molar mass= 88.148 g/mol
Quantity= 5.4 ml
Carboxylic acid= acetic acid
density= 1.05 g/ml
Molar mass= 60.052 g/mol
Quantity= 11.4 ml
and 1 ml of concentrated H2SO4 (1.8 g, 0.018 mole) was also used in the procedure.
Calculate theoretical yield and % yield .

Ester= Isoamyl acetate (banana) Molar mass of banana= 130.19 density= 0.876 g/ml 5.26 g ester product....
answer it all please
BS132 Experiment 3 2018-2019 The limiting reagent is the reagent which will completely react and so iIs excess. It will therefore be the reagent for which a lower number o present. Compare the respective molar proportions of the reagents used A and B above] and deduce which is the limiting reagent not in f moles are Igiven by Limiting reagent = 1 mark Scale of reaction (i.e. number of moles of limiting reagent used) - mol...
The density of a 8.01 m sulfuric acid solution is 1.354 g/mL. What is the molar concentration (molarity) of this solution? The molar mass of sulfuric acid, H2SO4, is 98.98 g/mol A. 6.07 M B.5.26 M C. 0.598 M D.4.20 M
Aspirin can be prepared from salicylic acid (C7H6O3), which has a molar mass of 138.12 g/mol, and acetic anhydride (C4H6O3), which has a molar mass of 102.04 g/mol. The density of acetic anhydride is 1.082 g/mL. C7H6O3+C4H6O3⟶C9H8O4+C2H3O2 What is the yield of aspirin (C9H8O4), which has a molar mass of 180.15 g/mol, possible when reacting 2.18 g of salicylic acid with 1.05 mL of acetic anhydride?
acetic acid is 25 ml and alcohol is 20 ml
The synthesis of an ester by the reaction of a carboxylic with an alcohol is an equilibrium reaction. H - R-OH HO ROH R OR, Recall from general chemistry that, according to Le Caiclista principle, an equilibrium can be shifted toward greater product formation by using an excess of reactant or by removal of a reaction product as it forms. 1. Are any products removed during the reaction period (the...
You mixed 5.25 g of methanol and a carboxylic acid whose molar mass is 138.12 g/mol and heated to obtain an ester. What is the molar mass (in g/mol) of the ester produced? Give a numerical answer to the nearest 0.01.
Vinegar is sold as % acidity which means a weight/volume or w/v% calculation. The density of acetic acid is 1.05 g/ml and water is (effectively) 1.0 g/ml. Recollect (from CHMY121) the %w/v refers to a solution with a certain mass of additive made up to 100 mL with the addition of (in this case) water; or % m/v= (grams of solute / 100 mL solution) ×100 The molar mass of Acetic Acid is 60.052 g/mol. What is the molarity of...
density= 1.08g/mL
molar mass = 102.09
DateULIT A. Preparation of Aspirin 2.931 mol EE 5.0 ml Mass of salicylic acid used Moles of salicylic acid used Volume of acetic anhydride used Moles of acetic anhydride used Identity of limiting reactant Theoretical yield of aspirin mol mol Calculations: B. 44.512 Yield Determination Mass of watch glass + filter paper Mass of watch glass, filter paper and dry aspirin Mass of dry aspirin Percent Yield Calculations: 103 Chemistry 131. EXPERIMENT 10
1-butanol yields 1-bromobutane in the presence of concentrated sulfuric acid and an excess of sodium bromide. CH3CH2CH2CH2OH (l) → CH3 CH2CH2CH2Br (l) If 17.12 mL of 1-butanol produced 14.77 g of 1-bromobutane, the percentage yield of the product equals: (Assume the density of 1-butanol is 0.81 g/mL, the molar mass of 1-butanol is 74 g/mol, and the molar mass of 1-bromobutane is 137 g/mol.) %
Aspirin can be prepared from salicylic acid (C7H6O3C7H6O3), which has a molar mass of 138.12 g/mol, and acetic anhydride (C4H6O3C4H6O3), which has a molar mass of 102.04 g/mol. The density of acetic anhydride is 1.082 g/mL. C7H6O3+C4H6O3⟶C9H8O4+C2H3O2C7H6O3+C4H6O3⟶C9H8O4+C2H3O2 What is the yield of aspirin (C9H8O4C9H8O4), which has a molar mass of 180.15 g/mol, possible when reacting 2.02 g of salicylic acid with 1.07 mL of acetic anhydride?
Compound molar mass density volume mmol equ 21% sodium ethoxide in ethanol 68.05 g/mol 0.868 g/mL 20 mL ~1.3 *1-bromobutane 137.02 g/mol 1.276 g/mL 4.5 mL ~1.0 *Limiting Reagent: 1-bromobutane I need help finding the mmol of sodium ethoxide in ethanol and 1-bromobutane. Also how to find the theoretical yield of this reaction from this graph?