Question

Compound molar mass density volume mmol equ 21% sodium ethoxide in ethanol 68.05 g/mol 0.868 g/mL...

Compound molar mass density volume mmol equ
21% sodium ethoxide in ethanol 68.05 g/mol 0.868 g/mL 20 mL ~1.3
*1-bromobutane 137.02 g/mol 1.276 g/mL 4.5 mL ~1.0

*Limiting Reagent: 1-bromobutane

I need help finding the mmol of sodium ethoxide in ethanol and 1-bromobutane. Also how to find the theoretical yield of this reaction from this graph?

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
Compound molar mass density volume mmol equ 21% sodium ethoxide in ethanol 68.05 g/mol 0.868 g/mL...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Compound Mol. Weight (g) mmol amount (in g or mL) melting point (°C) Density (g/mL) Ref....

    Compound Mol. Weight (g) mmol amount (in g or mL) melting point (°C) Density (g/mL) Ref. bromobenzene 157.01 4.00 0.628 n/a 1.491 1 magnesium powder 120.37 4.00 0.097 n/a n/a 2 ethyl ether 74.12 n/a 5.00 n/a 0.706 3 benzophenone 182.22 3.8 0.692 47-51 n/a 4 triphenylmethanol 260.33 160-163 n/a 5 5% HCl (aq.) 36.46 n/a 2.00 n/a n/a 6 With this information, what is the theoretical yield of triphenylmethanol? HO Br Mg MgBr ether ether bromobenzene benzophenone triphenylmethanol

  • what it is the theoretical yield of butyl methyl ether. 135 ml ethanol 4.77 g sodium...

    what it is the theoretical yield of butyl methyl ether. 135 ml ethanol 4.77 g sodium 20.55 g 1- Bromobutane

  • When 780 g of benzene (Molar mass = 78 g/mol) reacts with 750 mL of concentrated...

    When 780 g of benzene (Molar mass = 78 g/mol) reacts with 750 mL of concentrated HNO3 (16 M) and 750 mL of H2SO4 (18 M), 1000 g of nitrobenzene (molar mass = 123 g/mol) and 250 g of an unknown compound with a high boiling point are obtained. c. Give the name of the most probable side product with the high melting point. Explain why. e. Supposing the crystalline compound (250 g) has the formula C6H4N2O4, calculate the yield...

  • find limiting reagent? acetone 3.63 mL benzaldehyde 10.5mL bp (°C) mol. wt. (g/mole) 58.08 density (g/mL)...

    find limiting reagent? acetone 3.63 mL benzaldehyde 10.5mL bp (°C) mol. wt. (g/mole) 58.08 density (g/mL) 0.791 56 106.23 178-179 1.044 Acetone Benzaldehyde NaOH Dibenzalacetone 40.00 234.30 mp 110-111 9. Calculations for synthesis-moles of reactants, limiting reagent, theoretical yield , % experimental yield, show all math

  • What is the partial molar volume of ethanol (in units of mL/mol) in a solution with water if 168 mL of ethanol...

    What is the partial molar volume of ethanol (in units of mL/mol) in a solution with water if 168 mL of ethanol is added to 650. mL of water and the volume increases by only 153 mL ? Take the density of ethanol to be 0.789 g/mL.

  • Ester= Isoamyl acetate (banana) Molar mass of banana= 130.19 density= 0.876 g/ml 5.26 g ester product....

    Ester= Isoamyl acetate (banana) Molar mass of banana= 130.19 density= 0.876 g/ml 5.26 g ester product. Alcohol= isoamyl alcohol density= 0.81 g/ml Molar mass= 88.148 g/mol Quantity= 5.4 ml Carboxylic acid= acetic acid density= 1.05 g/ml Molar mass= 60.052 g/mol Quantity= 11.4 ml and 1 ml of concentrated H2SO4 (1.8 g, 0.018 mole) was also used in the procedure. Calculate theoretical yield and % yield .

  • density= 1.08g/mL molar mass = 102.09 DateULIT A. Preparation of Aspirin 2.931 mol EE 5.0 ml...

    density= 1.08g/mL molar mass = 102.09 DateULIT A. Preparation of Aspirin 2.931 mol EE 5.0 ml Mass of salicylic acid used Moles of salicylic acid used Volume of acetic anhydride used Moles of acetic anhydride used Identity of limiting reactant Theoretical yield of aspirin mol mol Calculations: B. 44.512 Yield Determination Mass of watch glass + filter paper Mass of watch glass, filter paper and dry aspirin Mass of dry aspirin Percent Yield Calculations: 103 Chemistry 131. EXPERIMENT 10

  • Exact mass of sodium bicarbonate: 2.110g Molar mass of sodium bicarbonate: 84.007 g/mol Molar mas...

    Exact mass of sodium bicarbonate: 2.110g Molar mass of sodium bicarbonate: 84.007 g/mol Molar mass of sodium acetate: 82.034 g/mol After you have recorded and any other glassware you have used. All waste can go down the sink. the mass of the beaker after the reaction, you may rinse out the beaker 10. CALCULATIONS: a) Rewrite the balanced chemical equation here Calculate the theoretical amount of sodium acetate that should be formed in the reaction (follow steps 1-3 below). b)...

  • please calculate the amount desired Reagent MW (g/mol) Equivs Mmol Density (g/mL) 122 123 1.34 4...

    please calculate the amount desired Reagent MW (g/mol) Equivs Mmol Density (g/mL) 122 123 1.34 4 Anisidine 1-Bromopropane K2CO3 Acetone Amount desired 0.122 g mL & ml 1 4 A ------- 138

  • 2.21 g of ethanol C2H5OH and 3.55 of oxygen O2 are reacted. Molar mass of C2H5Oh...

    2.21 g of ethanol C2H5OH and 3.55 of oxygen O2 are reacted. Molar mass of C2H5Oh 46.08 g/mol. O2 32.00 g/mol. Co2 44.01 g/mol. H20 18.02 g/mol a)What is the limiting reactant? b) what is the theoretical yield of carbon dioxide in grams will be obtained in the combustion reaction. starting with the amount of reagents given in part (a). assuming the reaction goes in 100% yield. c) If 0.951 f of CO2 is obtained from the reaction above, what...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT