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5) Zinc forms a precipitate with the hydroxide ion (Zn(OH)2) as well as several complex ions. Given the equilibria below, cal
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i) Zn(OH)2 29 = 0.732 x 10 3 M In (OH)₂ (s) en 2+ + 204 [oH ] = 2x 3.2 x 107 m. - 6. 4x107 Kep = [Zn2+ ] ron] ² [Zn2+] = ks =

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